6x^2+15x+4=0

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Solution for 6x^2+15x+4=0 equation:



6x^2+15x+4=0
a = 6; b = 15; c = +4;
Δ = b2-4ac
Δ = 152-4·6·4
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{129}}{2*6}=\frac{-15-\sqrt{129}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{129}}{2*6}=\frac{-15+\sqrt{129}}{12} $

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